Improve Tuition · Foundation Maths · Grade 4–6
Prime Factorisation — Lesson & Practice Paper

Prime Factorisation

Prime numbers, factor trees, indices, and applications · Grade 4–6.

This booklet helps you learn about factors, step by step.

What’s a factor?

A factor is a number that fits exactly into another number — with nothing left over.

Example: 12 ÷ 3 = 4. Three fits exactly into twelve, so 3 is a factor of 12.

The factors of 12 are: 1, 2, 3, 4, 6, 12.

What you’ll learn

By the end of this paper you will be able to recognise primes, write a number as a product of its prime factors, use index notation, reason with perfect squares and cubes, and read structural facts — such as the number of factors and the biggest odd factor — straight from a factorisation. Each section opens with its own learning objective and success criteria — check these before you start the section and again when you finish. HCF and LCM are covered in the separate LCM and HCF paper.

How to use the booklet

There are seven short sections (A–G). Sections A–D are calculation questions: recognise primes, factor trees, index notation, applications. Sections E–G are word problems, easier to harder.

If you get stuck, that’s OK — stop there. The section you stop at tells your tutor exactly where you need help.

TUTOR — MATERIALS TO HAVE READY

For pupils who learn best with physical things to handle:

The seven sections:
· Section A — Recognising primes. Decide whether a number is prime.
· Section B — Factor trees. Break a number down into its prime factors.
· Section C — Index notation. Evaluate basic powers such as 2³ and 3².
· Section D — Applications. Perfect squares, perfect cubes, smallest multipliers.
· Section E — Real-life applications. Word problems using prime factorisation.
· Section F — Squares and cubes in context. Word problems with perfect squares and cubes.
· Section G — Structural reasoning. Biggest odd factor and other structural questions.
Lesson 1

Prime factors, factor trees, and index form

Aim: Write a whole number as a product of its prime factors, then in index form using powers like 2³.

A prime factor is simply a factor that is also a prime number. The clever part is that every whole number bigger than 1 can be built by multiplying prime factors together — and that product is called its prime factorisation.

Examples:
· 12 = 2 × 2 × 3
· 30 = 2 × 3 × 5
· 100 = 2 × 2 × 5 × 5
Notice that each factorisation contains only prime numbers, multiplied together.

The factor tree method:

  1. Start with the number at the top.
  2. Split it into any factor pair (two numbers that multiply to give it).
  3. If a branch ends in a prime, circle it and stop that branch.
  4. If a branch ends in a composite, split it again.
  5. When every branch ends in a prime, multiply the leaves together — that’s the prime factorisation.

Let’s build the tree for 60 step by step, then look at the finished result.

Worked example
Find the prime factorisation of 60.
  1. 60 = 2 × 30.
  2. 2 is prime. Stop that branch.
  3. Split 30: 30 = 2 × 15.
  4. 2 is prime. Split 15.
  5. 15 = 3 × 5. Both prime — stop.
  6. Collect leaves: 2, 2, 3, 5.
  7. So 60 = 2 × 2 × 3 × 5.

Drawn out, that tree looks like this — every leaf is a prime, and the 2 that appears twice is what becomes 2² in a moment:

Factor tree for 60 60 2 30 2 15 3 5 prime (stop here) composite (split again) 60 = 2 × 2 × 3 × 5 = 2² × 3 × 5

Index form is a shorthand for repeated multiplication. A power is the small raised number you see in something like 23. It tells you how many copies of the base number to multiply together. The power is NOT a normal multiplier.

Examples of powers:
· 23 means 2 × 2 × 2 = 8.  Read as “two cubed” or “two to the power of three”.
· 52 means 5 × 5 = 25.  Read as “five squared”.
· 24 means 2 × 2 × 2 × 2 = 16.  Read as “two to the power of four”.
Watch out — the most common index-form error

23 is NOT 2 × 3 = 6.

23 IS 2 × 2 × 2 = 8.

The raised number tells you HOW MANY copies of the base to multiply together, not what to multiply the base BY.

Worked example
Write 60 in index form.
  1. From the factor tree: 60 = 2 × 2 × 3 × 5.
  2. 2 appears twice — write 22.
  3. 3 appears once — just 3 (no power needed).
  4. 5 appears once — just 5.
  5. So 60 = 22 × 3 × 5.

Try one

Find the prime factorisation of 48 in index form.

Show answer
Divide by the smallest prime each time: 48 = 2×24 = 2×2×12 = 2×2×2×6 = 2×2×2×2×3.
Four 2s and one 3.
Index form: 2⁴ × 3.
Check: 16 × 3 = 48. ✓
Practise this now — Section B & C →
Lesson 2

Perfect squares and cubes from prime factorisation

Aim: Decide whether a number is a perfect square or cube using its prime factorisation. Find the smallest multiplier that turns a number into a perfect square or cube.

By now you can break any number into its prime factors with a factor tree. That factorisation is the key to this lesson: it shows at a glance whether a number is a perfect square or a perfect cube.

A perfect square is an integer you get by squaring an integer: 1, 4, 9, 16, 25, 36, 49, … A perfect cube is one you get by cubing: 1, 8, 27, 64, 125, 216, …

The criterion (from prime factorisation):
A number is a perfect square if and only if every prime in its factorisation has an EVEN power.
A number is a perfect cube if and only if every prime power is a MULTIPLE OF 3.
Worked example
Is 144 a perfect square?
  1. Prime factorise: 144 = 16 × 9 = 24 × 32.
  2. Power of 2 is 4 (even). Power of 3 is 2 (even).
  3. Both powers are even — so 144 IS a perfect square.
  4. Check: 144 = 122. ✓
WHY THIS WORKS

Suppose n = pa × qb. Then √n = pa/2 × qb/2.

For √n to be a whole number, the halved powers a/2 and b/2 must be whole numbers — meaning a and b must be even.

Same logic for cubes: ∛n is whole only when every prime power divides cleanly by 3.

Worked example
Find the smallest k > 0 such that 18k is a perfect square.
  1. Prime factorise 18: 18 = 2 × 32.
  2. For 18k to be a perfect square, every prime power must be EVEN.
  3. Power of 2 is 1 (odd) — need one more 2 to bump to 22.
  4. Power of 3 is 2 (even) — fine, leave alone.
  5. So k must contribute exactly one 2: k = 2.
  6. Check: 18 × 2 = 36 = 62. ✓
Worked example
Find the smallest k > 0 such that 24k is a perfect cube.
  1. Prime factorise 24: 24 = 23 × 3.
  2. For 24k to be a perfect cube, every prime power must be a MULTIPLE OF 3.
  3. Power of 2 is 3 (already a multiple of 3) — fine.
  4. Power of 3 is 1 — need to bump to 3. Add two more 3s.
  5. So k = 32 = 9.
  6. Check: 24 × 9 = 216 = 63. ✓

Try one

Find the smallest k > 0 such that 50k is a perfect square.

Show answer
50 = 2 × 5².
The power of 2 is odd; a square needs even powers.
Multiply by one more 2: k = 2.
Check: 50 × 2 = 100 = 10². ✓
Practise this now — Section D →
Lesson 3

Reading facts straight from a prime factorisation

Aim: Once a number is written as a product of primes, read off useful facts — how many factors it has, its biggest odd factor, and what it divides — without working out the whole number.

A prime factorisation is like a number’s blueprint. Earlier you used it to spot perfect squares and cubes; here you use the same blueprint to answer questions that would be slow to do by hand.

Skill 1 — How many factors? Every factor is built by choosing how many of each prime to include. If a prime appears to the power a, you may take 0, 1, 2, … up to a of it — that is a + 1 choices. Multiply the choices across all the primes.

Number of factors of pa × qb × … = (a + 1)(b + 1)…
Worked example
How many factors does 2² × 3² × 5 have?
  1. The 2 can appear 0, 1 or 2 times — 3 choices.
  2. The 3 can appear 0, 1 or 2 times — 3 choices.
  3. The 5 can appear 0 or 1 times — 2 choices.
  4. Multiply the choices: 3 × 3 × 2 = 18 factors.

Skill 2 — The biggest odd factor. Any factor that contains a 2 is even. So to find the biggest odd factor, simply drop every 2 and keep all the rest.

Worked example
Find the biggest odd factor of 2³ × 3².
  1. The 2s are the only thing that can make a factor even — drop all three of them.
  2. What remains is 3² = 9.
  3. So the biggest odd factor is 9 — found without ever working out that the number is 72.

Skill 3 — Does one number divide another? One number divides another exactly when every prime power in the first is no bigger than the matching power in the second.

Worked example
Does 12 divide 360?
  1. Write both in prime form: 12 = 2² × 3,   360 = 2³ × 3² × 5.
  2. Power of 2: the 2² in 12 fits inside the 2³ in 360. ✓
  3. Power of 3: the 3¹ in 12 fits inside the 3² in 360. ✓
  4. Every prime in 12 fits, so yes — 12 divides 360 (and 360 ÷ 12 = 30).
Watch out — the “+ 1” when counting factors

Use (a + 1), not a. The “+ 1” is there because a prime can also appear zero times in a factor.

For 2² × 3² × 5 the answer is 3 × 3 × 2 = 18, not 2 × 2 × 1 = 4. Always multiply the (power + 1) values, never the powers themselves.

Try one

A number is 24 × 7.  (a) How many factors does it have?  (b) What is its biggest odd factor?

Show answer
(a) Add one to each power and multiply: (4 + 1)(1 + 1) = 5 × 2 = 10 factors.
(b) Drop the 2s, leaving 7. ✓
Practise this now — Section G →
VOCABULARY
Factor
A whole number that divides another exactly. 3 is a factor of 12.
Prime number
A whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, …
Composite number
A whole number with more than 2 factors. 12 is composite. (1 is neither prime nor composite.)
Prime factor
A factor that is itself prime. The prime factors of 12 are 2 and 3.
Prime factorisation
A number written as a product of its prime factors. 12 = 22 × 3.
Factor tree
A diagram for finding the prime factorisation. Split, keep splitting, stop when every branch is prime.
Index form (or power form)
A shorthand for repeated multiplication. 23 means 2 × 2 × 2 = 8.
Perfect square
A whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN.
Perfect cube
A whole number you get by cubing an integer: 1, 8, 27, 64, … In prime factorisation, every prime power is a MULTIPLE OF 3.

Recap before you start the paper

Part Two

Now try the practice questions

35 questions across seven sections. No time pressure when you’re ready. The step-by-step walkthroughs unlock after you mark.

Instructions

Take your time

No time pressure

Work carefully. Your tutor is looking for understanding, method, and the point where you begin to struggle.

↑ Back to the lessons
Section A · Recognising primes

Decide whether a number is prime.

LEARNING OBJECTIVE 1 · GRADE 1

Recognise prime numbers.

Success criteria — I can:
  • list the first ten primes (2, 3, 5, 7, 11, 13, 17, 19, 23, 29)
  • decide whether a given number is prime by checking its factors
  • explain why 1 is not prime and why 2 is the only even prime
Q1.
Is 7 a prime numberA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime.?
Your answer:
(1 mark)
Q2.
Is 9 a prime numberA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime.?
Your answer:
(1 mark)
Q3.
Is 1 a prime numberA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime.?
Your answer:
(1 mark)
Q4.
Write the smallest prime numberA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime..
Your answer: (1 mark)
Q5.
List the five prime numbersA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime. between 10 and 25.
Your answer:
,,,,
(5 marks)
↑ Back to the lessons
Section B · Factor trees

Write a number as a product of its prime factors using a factor tree.

LEARNING OBJECTIVE 2 · GRADE 4

Build a factor tree and write a number as a product of its prime factors.

Success criteria — I can:
  • split a composite number into a factor pair
  • keep splitting until every branch ends at a prime
  • write the prime factorisation as a multiplication (e.g. 12 = 2 × 2 × 3)
  • check my answer by multiplying the primes back together
Q6.
Write 12 as a productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of three prime factorsA factor that is itself a prime number. The prime factors of 12 are 2 and 3.. Type each primeA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime. in a box (in any order).
Your answer:
,,
(4 marks)
Q7.
Write 60 as a productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of four prime factorsA factor that is itself a prime number. The prime factors of 12 are 2 and 3..
Your answer:
,,,
(4 marks)
Q8.
Write 54 as a productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of four prime factorsA factor that is itself a prime number. The prime factors of 12 are 2 and 3..
Your answer:
,,,
(4 marks)
Q9.
Write 180 as a productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of five prime factorsA factor that is itself a prime number. The prime factors of 12 are 2 and 3..
Your answer:
,,,,
(5 marks)
Q10.
Write 84 as a productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of four prime factorsA factor that is itself a prime number. The prime factors of 12 are 2 and 3..
Your answer:
,,,
(5 marks)
↑ Back to the lessons
Section C · Index notation

Evaluate basic powers. Convert between prime factorisation and the number.

LEARNING OBJECTIVE 3 · GRADE 4

Evaluate basic index notation and use it to write prime factorisations.

Success criteria — I can:
  • work out a power correctly (e.g. 2³ = 8, NOT 2 × 3)
  • rewrite repeated prime factors using powers (e.g. 2 × 2 × 2 × 3 = 2³ × 3)
  • convert between index form and the number it represents
Q11.
What does equal?
Your answer: (1 mark)
Q12.
What does equal?
Your answer: (1 mark)
Q13.
What does 3⁴ (3 to the power of 4) equal?
Your answer: (2 marks)
Q14.
A number has prime factorisationA number written as a product of its prime factors, often in index form. 12 = 2² × 3. 2³ × 3² × 5. What is the number?
Your answer: (2 marks)
Q15.
A number has prime factorisationA number written as a product of its prime factors, often in index form. 12 = 2² × 3. 2² × 3 × 7. What is the number?
Your answer: (2 marks)
↑ Back to the lessons
Section D · Applications

Perfect squares and cubes. Smallest-k multipliers.

LEARNING OBJECTIVE 4 · GRADE 4–5

Identify perfect squares and perfect cubes from prime factorisation.

Success criteria — I can:
  • decide if a number is a perfect square by checking that every prime power is EVEN
  • decide if a number is a perfect cube by checking that every prime power is a MULTIPLE OF 3
  • find the smallest k that makes nk a perfect square or cube
Q16.
Is 196 a perfect squareA whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN.?
Your answer:
(2 marks)
Q17.
Is 250 a perfect squareA whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN.?
Your answer:
(2 marks)
Q18.
Find the smallest positive integer k such that 18k is a perfect squareA whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN..
Your answer: (3 marks)
Q19.
Find the smallest positive integer k such that 72k is a perfect cubeA whole number you get by cubing an integer: 1, 8, 27, 64, 125, … In prime factorisation, every prime power is a MULTIPLE OF 3..
Your answer: (3 marks)
Q20.
A number is 2² × 3 × 5. How many different factorsA whole number that divides another exactly, with no remainder. 3 is a factor of 12 because 12 ÷ 3 = 4. does it have in total (including 1 and itself)?
Your answer: (3 marks)
↑ Back to the lessons
Section E · Real-life applications

Word problems: packing, grouping, splitting equally.

LEARNING OBJECTIVE 5 · GRADE 4

Apply prime factorisation to real-life contexts.

Success criteria — I can:
  • recognise when a real-life problem needs factor-based reasoning
  • use prime factorisation to find how groups, packs or rows divide evenly
  • check that the answer makes sense in context
Q21.
A number is the productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of 2 × 3 × 5. What is the number?
Your answer: (1 mark)
Q22.
A box of 40 chocolates is to be split into a number of equal piles. What is the prime factorisationA number written as a product of its prime factors, often in index form. 12 = 2² × 3. of 40? Type just the productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. (e.g. for 12 = 2²×3, type 12).
Your answer: (2 marks)
Q23.
A football tournament has 36 teams arranged in equal groups. The prime factorisationA number written as a product of its prime factors, often in index form. 12 = 2² × 3. of 36 is 2² × 3². How many different ways can the teams be split into equal groups (any group size ≥ 2 and < 36)?
Your answer: (2 marks)
Q24.
A school has 2³ × 3 classrooms. How many classrooms is that?
Your answer: (2 marks)
Q25.
48 cookies. Write 48 as a productThe result of multiplying. 5 × 4 = 20, so 20 is the product of 5 and 4. of five prime factorsA factor that is itself a prime number. The prime factors of 12 are 2 and 3..
Your answer:
,,,,
(3 marks)
↑ Back to the lessons
Section F · Squares and cubes in context

Word problems with perfect squares and cubes.

LEARNING OBJECTIVE 4 · GRADE 5

Apply perfect-square and perfect-cube reasoning to word problems (LO 4 in context).

Success criteria — I can:
  • spot when a word problem requires a perfect square or cube
  • use prime factorisation to find a missing side or count
  • check by squaring or cubing back
Q26.
A square sticker album has n stickers per row and n rows. There are 144 stickers in total. What is n?
Your answer: (2 marks)
Q27.
A toy company packs 200 toys into boxes. The number of boxes must be a factorA whole number that divides another exactly, with no remainder. 3 is a factor of 12 because 12 ÷ 3 = 4. of 200. Using 200 = 2³ × 5², find the total number of factorsA whole number that divides another exactly, with no remainder. 3 is a factor of 12 because 12 ÷ 3 = 4. (and so total possible box counts including 1 and 200).
Your answer: (2 marks)
Q28.
Sara is building a perfect squareA whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN. garden out of 50 identical small square tiles. She doesn’t have enough — she needs to buy more identical tiles so the total IS a perfect squareA whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN.. What is the smallest number of extra tiles she needs to buy?
Your answer: (3 marks)
Q29.
A cubic crate holds n × n × n identical boxes. The crate holds 216 boxes. What is n?
Your answer: (3 marks)
Q30.
James has 50 marbles. He wants to arrange them in a perfect cubeA whole number you get by cubing an integer: 1, 8, 27, 64, 125, … In prime factorisation, every prime power is a MULTIPLE OF 3. pattern. He buys more marbles. What is the smallest number of extra marbles he needs?
Your answer: (3 marks)
↑ Back to the lessons
Section G · Structural reasoning

Biggest odd factor and other structural questions.

LEARNING OBJECTIVE 6 · GRADE 5

Use the structure of a prime factorisation to reason without doing big calculations.

Success criteria — I can:
  • find the biggest odd factor of a number by dropping the 2s
  • decide whether one number is divisible by another using prime factorisations
  • count how many factors a number has by listing systematically
Q31.
A number is 2² × 3² × 5. How many different factorsA whole number that divides another exactly, with no remainder. 3 is a factor of 12 because 12 ÷ 3 = 4. does the number have?
Your answer: (3 marks)
Q32.
Find the smallest positive integer k such that 75k is a perfect squareA whole number you get by squaring an integer: 1, 4, 9, 16, 25, … In prime factorisation, every prime power is EVEN..
Your answer: (3 marks)
Q33.
A factory packs identical items into cubic crates of side n. The crate must hold MORE than 1000 items. What is the smallest cube numberA whole number you get by cubing an integer: 1, 8, 27, 64, 125, … In prime factorisation, every prime power is a MULTIPLE OF 3. greater than 1000?
Your answer: (3 marks)
Q34.
A whole numberA number with no fractional part: 0, 1, 2, 3, 4, … has exactly 9 factorsA whole number that divides another exactly, with no remainder. 3 is a factor of 12 because 12 ÷ 3 = 4.. The smallest such number using only the primesA whole number bigger than 1 with exactly 2 factors: 1 and itself. 2, 3, 5, 7, 11, … 1 is NOT prime. 2 and 3 in its prime factorisationA number written as a product of its prime factors, often in index form. 12 = 2² × 3. is … ?
Your answer: (3 marks)
Q35.
A number is 2³ × 3². Without working out the whole numberA number with no fractional part: 0, 1, 2, 3, 4, …, find the biggest odd factorA whole number that divides another exactly, with no remainder. 3 is a factor of 12 because 12 ÷ 3 = 4..
Your answer: (3 marks)
Question 1 of 35 · 0 answered